13.7x^2+x-0.5=0

Solution for 13.7x^2+x-0.5=0 equation:

13.7x^2+x-0.5=0

a = 13.7; b = 1; c = -0.5;
Δ = b2-4ac
Δ = 12-4·13.7·(-0.5)
Δ = 28.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{28.4}}{2*13.7}=\frac{-1-\sqrt{28.4}}{27.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{28.4}}{2*13.7}=\frac{-1+\sqrt{28.4}}{27.4}
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